MATH SOLVE

4 months ago

Q:
# A game spinner has eight equal sections: three sections numbered 1, one section numbered 2, and four sections numbered 3. The spinner is spun twice. What is the probability that the sum of the two spins will be five?

Accepted Solution

A:

Answer:The required probability is [tex]\frac{1}{8}[/tex] or 0.125Step-by-step explanation:Consider the provided information.The spinner is spin twice and we want the sum should be 5.We can get 5 if first spin gives us 2 and second spin gives 3.Or we can get 5 if first spin gives us 3 and second spin gives 2.There are 8 section out off which Three sections numbered 1, one section numbered 2, and four sections numbered 3. The probability of getting 2 is [tex]\frac{1}{8}[/tex]The probability of getting 3 is [tex]\frac{4}{8}[/tex]Now, the probability that the sum of the two spins will be five is:[tex]\frac{1}{8}\times \frac{4}{8}+\frac{4}{8}\times \frac{1}{8} =\frac{4}{64}+\frac{4}{64}=\frac{1}{8}[/tex]Hence, the required probability is [tex]\frac{1}{8}[/tex] or 0.125