Solve the equation for xx. For each step, describe the operation used to convert the equation.3x−[8−3(x−1)]=x+19

Answer:x = 6Step-by-step explanation:Equation given in the question:3x − [ 8 − 3(x−1) ] = x + 19Now,multiplying the term (3(x-1)) in the equation, we get⇒ 3x - [ 8 - 3x -3 × (-1)] = x + 19or⇒ 3x - [ 8 -3x +3 ] = x + 19or⇒ 3x - [ 11 -3x ] = x + 19now,multiplying opening the bracket [11 - 3x]⇒ 3x - 11 - (-3x) = x + 19or⇒ 3x - 11 + 3x = x + 19on adding the terms with same coefficient 'x' on LHS⇒ (3 + 3)x - 11 = x + 19 or⇒ 6x - 11 = x + 19taking -11 to the RHS⇒ 6x = x + 19 + 11or⇒ 6x = x + 30subtracting x both the sides⇒ 6x - x = x + 30 - xor5x = 30dividing the both sides by 5[tex]\frac{5x}{5}= \frac{30}{5}[/tex]therefore,x = 6